On request of Shamas Akhtar Awan :
This is the function to return a string of binary equivalent of an int. The function takes in an integer value and returns a string of 0′s and 1′s of binary equavalet of that integer.
char * int2binarystr(int value) {
char binstr[23];// adjust the size of the string to your needs
int i,b;
b=value;
i=0;
while(b>0)
{
binstr[i]=b%2;
b=b/2; i++;
}
binstr[i]=00;
return binstr; // returns the string
}
You can use this in your code as needed. One example is to write to uart the string
Uart0_write_text(int2binarystr(20)); // writes the string conataing the binary equavalent of 20 to uart
One more doubt, in this line char * int2binarystr(int value) , what is the use of * , can u explain what happen if we don't write * …… I write function without * so can u explain this point
The function returns a pointer to the string to which it will write the binary equivalent. If you skip * it will return a char value instead of pointer
Ahh thanks to point out that , the syntax highlighter is making a problem I wrote '' there Null value – changed it to 00